Good evening SpudFiles!
I just got an idea, when you make a semi-automatic cadridge ejecting gun, to make it have the best power you need to make a gas piston on the barrel to open the bolt lock, am i right? So, i was desingning a cardridge ejecting hybrid that would imitate the Barret M82A1, i started thinking the bolt lock. Then it hit me. Bolt lock would be a strong solenoid, and it would be opened when the bullet travels through the IR sensor on the muzzle, causing the pressure in the barrel push the bolt with weak spring back, ejekting the shell and loading a new one. Only question is, would this work?
using solenoid and IR sensor as boltlock on cardridge hybrid
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POLAND_SPUD
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yeswould this work?
Is it practical? No it isn't. You can achieve the same result if you hook up an air cylinder to the chamber
Children are the future
unless we stop them now
unless we stop them now
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Technician1002
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If your bolt has for example 20 times the mass of the projectile and propellant gas, then the bolt could be ejected rearward at 1/20th the speed of the projectile.
In theory, the bolt could have moved back 1 inch in the same time the projectile exits the barrel.
Most semi and full auto weapons use this physics principal instead of detecting the projectile. You can use the bolt in place of the air cylinder.
For every action there is an equal but opposite reaction.
An object in motion will remain in motion unless an external force is applied. This gives us the F=MA formula.
http://www.racemath.info/forcesandpress ... s_f=ma.htm
The slide on a semi-automatic pistol is much heavier than the projectile. It travels much slower than the projectile and finishes ejecting the casing long after the round is gone.
In theory, the bolt could have moved back 1 inch in the same time the projectile exits the barrel.
Most semi and full auto weapons use this physics principal instead of detecting the projectile. You can use the bolt in place of the air cylinder.
For every action there is an equal but opposite reaction.
An object in motion will remain in motion unless an external force is applied. This gives us the F=MA formula.
http://www.racemath.info/forcesandpress ... s_f=ma.htm
The slide on a semi-automatic pistol is much heavier than the projectile. It travels much slower than the projectile and finishes ejecting the casing long after the round is gone.
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jakethebeast
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so, it would be like a recoil operated or "mass-lock" (rough translate).
I think il just make a prototype out of the cardridge today and see if it would work
I think il just make a prototype out of the cardridge today and see if it would work
The solenoid set-up allows for a lighter bolt using less energy.
I could be more compact than a cylinder set up.
The issues I see would be getting it to react fast enough while still being robust enough to absorb the shock on the bolt.
I could be more compact than a cylinder set up.
The issues I see would be getting it to react fast enough while still being robust enough to absorb the shock on the bolt.
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Technician1002
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The amount of energy is related to the mass of the bolt in relation to the mass of the projectile in an inverse relationship. For less energy in the bolt, make it higher mass so it moves less during the shot.
Energy whether measured in foot lbs or newton meters, is a relationship of force and distance. The less the high mass moves during the application of force the less energy it has. The bolt may move 2 inches for the entire cycle, but if the shot applied force for only the first 1/2 inch, the energy is based on the 1/2 inch the force was applied, not how far it traveled after the force ended.
Energy whether measured in foot lbs or newton meters, is a relationship of force and distance. The less the high mass moves during the application of force the less energy it has. The bolt may move 2 inches for the entire cycle, but if the shot applied force for only the first 1/2 inch, the energy is based on the 1/2 inch the force was applied, not how far it traveled after the force ended.